Mikes older brother, Jeff, beta him that he can't roll two dice and get doubles three times in a row. If mike does it, Jeff will give him $100.00. Otherwise, mike had to give Jeff $5.00. What is the expected value of mike's bet?
So first we need to find the probability of rolling the 2 dice and both landing on 6 one time, which because there is a total of 36 total possibilities that could come from rolling 2 dice it would be a 1/36 chance of getting a double 6's on 2 dices, now if we want to do this 3 times in a row we need to multiply are odds by 2 more 36's so it would look like this 1/36*1/36*1/36=1/46656 so you would have a one in 46656 chance of doing this. Ill have to get back to you about the value need to research that up hope this helps for now!
