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find the length and width of a rectangular lot with a perimeter of 68m if the length is 6m more than the width



Answer :

AyaZ
[tex]l=w+6[/tex]
[tex]P=2(l+w)=68[/tex]
[tex]P=2((w+6)+w)=2(2w+6)=4w+12=68[/tex]
[tex]4w=56 \\ w=14[/tex]
[tex]l=w+6=14+6=20[/tex]

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