Answer :

crisforp
x<2 and x>-3 => x∈(-oo, 2) and x ∈(-3,+oo )=> x∈(-3, 2).

7x < 14

x < 14/7

x < 2

x ∈ (-oo ; 2)

1 - x < 4

1 - 4 < x

- 3 < x

x > - 3

x ∈ (- 3 ; + oo)

_____(.__.__.__.__.__.)____

-oo   - 3             0         2

x ∈ (- 3 ; 2 )

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