Answer :
area for a trapezoid is A= a+b/2 times h (a and b are the bases which are 8 and 10
so 108=8+10/2 x h 8+10 divided by 2 equals 9 so now we have 108=9 x h
now we must divide both sides by 9 to solve for the height 108/9 equals 12 so the height of the trapezoid is 12
so 108=8+10/2 x h 8+10 divided by 2 equals 9 so now we have 108=9 x h
now we must divide both sides by 9 to solve for the height 108/9 equals 12 so the height of the trapezoid is 12
The area of the trapezoid is given by the formula A= (a+b)/ 2 * h
in this question a= 8, b= 10, A= 108 inches², and h is what we have to find, substitute what we have got into the formula and you will have:
108= (8+10) /2 *h
108= 9 *h
h= 108/9
h= 12 inches