Answer :

SoapyMcTavish
First of all, you add 1/3 and 4/5, so you get:
[tex] \frac{1}{3} + \frac{4}{5} [/tex]

To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
[tex] \frac{1*5}{3*5} + \frac{4*3}{5*3} [/tex]
[tex] \frac{5}{15} + \frac{12}{15} [/tex]

Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
[tex] \frac{5+12}{15} [/tex]
[tex] \frac{17}{15} [/tex]

That's the sum of 1/3 + 4/5.

Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
[tex] \frac{17}{15} * \frac{7}{1} [/tex]

In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
[tex] \frac{17*7}{15*1} [/tex]
[tex] \frac{119}{15} [/tex]

Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15. 

Hope this Helps! :D
soneyedesola44

What you have to do first is to add [tex]\frac{1}{3}[/tex] and [tex]\frac{4}{5}[/tex],

Further Explanation

Therefore we have:

= [tex]\frac{1}{3}[/tex] + [tex]\frac{4}{5}[/tex]

= ( [tex]\frac{1}{3}[/tex] + [tex]\frac{4}{5}[/tex] ) / 15 (15 is the smallest number that divide both denominator also known as LCD)

= (5 x 1) + (3 x 4) / 15

= 5 + 12 / 15

= [tex]\frac{17}{15}[/tex]

Therefore, the sum of [tex]\frac{1}{3}[/tex] + [tex]\frac{4}{5}[/tex] is [tex]\frac{17}{15}[/tex]

But since the question says you should determine the sum of the 2 fractions, therefore you should multiply [tex]\frac{17}{15}[/tex] by 7. Therefore you should have:

[tex]\frac{17}{15}[/tex] X 7 (7 can also be expressed as [tex]\frac{7}{1}[/tex])

= [tex]\frac{17}{15}[/tex] x [tex]\frac{7}{1}[/tex] (notably, in multiplication there is no need for the fraction to have the same denominator. You can multiply both numbers at the top together (numerator) and do same with the denominator.

= [tex]\frac{119}{15}[/tex]

= [tex]7\frac{14}{15}[/tex]

Therefore, 7 times as much as the sum of [tex]\frac{1}{3}[/tex] and [tex]\frac{4}{5}[/tex] is [tex]7\frac{14}{15}[/tex]

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  • 7 times as much as the sum of 1/3 and 4/5  https://brainly.com/question/282415

KEYWORDS:

  • multiplication
  • addition
  • sum
  • denominator
  • numerator