Answer :

[tex]f(x)=2x^2+5\sqrt{x+2}\\\\f(0)\to substitute\ x=0:\\\\f(0)=2\cdot0^2+5\sqrt{0+2}=0+5\sqrt2=5\sqrt2\approx5\cdot1.41=7.05[/tex]
abidemiokin

The value of the expression to the nearest hundredth is 7.07

Functions and values

Functions are expression written in terms of variable. The variables are in represented using letters.

Given the following function expressed as;

[tex]f(x)=2x^2+5\sqrt{x+2}[/tex]

In order to determine the value of f(0), substitute x = 0 into the function to have:

[tex]f(0)=2(0)^2+5\sqrt{0+2}\\f(0) = 5\sqrt{2}[/tex]

Hence the value of the expression to the nearest hundredth is 7.07

Learn more on functions here: https://brainly.com/question/25638609

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