Answer :
[tex]9x+6=3[/tex] /-6
[tex]9x=-3 \\ \\ x=- \frac{3}{9} ^{/3}=- \frac{1}{3} [/tex]
[tex]\sf9x+6=3[/tex]
Subtract 6 to both sides:
[tex]\sf9x=-3[/tex]
Divide 9 to both sides:
[tex]\sf~x=-\dfrac{1}{3}[/tex]
Subtract 6 to both sides:
[tex]\sf9x=-3[/tex]
Divide 9 to both sides:
[tex]\sf~x=-\dfrac{1}{3}[/tex]