Answer :
M(Na2CO3)=2M(Na)+M(C)+3M(O)
=2(23)+12+3(16)
=46+12+48
=106 g/mol
the molar mass of Na2CO3 is 106 g/mol
m=106g M=106 g/mol n=m/M
n=m/M n=106/106 n=1mol
=2(23)+12+3(16)
=46+12+48
=106 g/mol
the molar mass of Na2CO3 is 106 g/mol
m=106g M=106 g/mol n=m/M
n=m/M n=106/106 n=1mol
The molarity of the solution is the ratio of moles of solute to the volume of the solution in L. The molar mass of sodium carbonate is 106 g/mol and molarity is 0.167 M.
What is molar mass?
Molar mass is the mass of the compound that is given by the addition of the atomic mass of the individual atom present in the compound with respect to their stoichiometry coefficients.
The molar mass (M) of sodium carbonate can be given as,
[tex]\rm M(Na_{2}CO_{3}) = 2M(Na)+M(C)+3M(O)[/tex]
Here mass of sodium = 23, carbon = 12 and oxygen = 16
Substituting values of the atomic mass we get:
[tex]\begin{aligned} &=2(23)+12+3(16)\\\\&=46+12+48\\\\&=106 \;\rm g/mol\end{aligned}[/tex]
Hence, the molar mass of sodium carbonate is 106 g/mol.
Now molarity of sodium carbonate can be estimated as:
[tex]\begin{aligned}\rm Molarity &= \rm \dfrac{mass}{\rm molar \; mass \times Volume}\\\\&= \dfrac{106}{106 \times 6}\\\\&= 0.16 \;\rm M\end{aligned}[/tex]
Therefore, 106 g/mol is the molar mass and 0.16 M is the molarity of sodium carbonate.
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