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a 6-kg and a 4-kg ball are acted on by forces of equal size. if the large ball accelerates at 2 m/s2 what acceleration will the small ball undergo



Answer :

To answer this question, we need to find the force acting on the two objects.

f=ma
f=(6)(2)
f=12 newtons

So, now we can determine the acceleration of the second object using the same formula!

f=ma
12=(4)a
3=a

So the acceleration of the smaller object is 3 meters per second squared!

It would be 30 meters.

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