Answer :
[tex]6x+5y=7 \\
2x-4y=-26 \ \ \ |\hbox{multiply by (-3)} \\ \\
6x+5y=7 \\
\underline{-6x+12y=78} \ \ \ |\hbox{add the sides} \\
5y+12y=7+78 \\
17y=85 \ \ \ |\hbox{divide by 17} \\
y=5 \\ \\
\hbox{substitute 5 for y:} \\
6x+5y=7 \\
6x+5 \times 5=7 \\
6x+25=7 \ \ \ |\hbox{subtract 25} \\
6x=-18 \ \ \ |\hbox{divide by 6} \\
x=-3 \\ \\
\boxed{(x,y)=(-3,5)}[/tex]