Answer :
If f(x) = 2x - 5 and g(x) = x + 52, then f(g(x)) can be deduced by placing g(x) in the spot of x in the f(x) equation as follows:
f(g(x)) = 2(g(x)) - 5
Since we know g(x) = x + 52, let's plug it in:
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
f(g(x)) = 2(g(x)) - 5
Since we know g(x) = x + 52, let's plug it in:
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
f(x) = 2x - 5
g(x) = x + 52
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2(x) + 2(52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
or
f(x) = 2x - 5
g(x) = x + 52
f(g(x)) = f(x + 52)
f(g(x)) = (x + 52) + 52
f(g(x)) = x + (52 + 52)
f(g(x)) = x + 104
g(x) = x + 52
f(g(x)) = 2(x + 52) - 5
f(g(x)) = 2(x) + 2(52) - 5
f(g(x)) = 2x + 104 - 5
f(g(x)) = 2x + 99
or
f(x) = 2x - 5
g(x) = x + 52
f(g(x)) = f(x + 52)
f(g(x)) = (x + 52) + 52
f(g(x)) = x + (52 + 52)
f(g(x)) = x + 104
