so x+y=-14
xy=-240
x+y=-14
subtract y from both sides
x=-14-y
subsitute for x in second equation
(-14-y)y=-240
multiply
-y^2-14y=-240
add y^2+14y to both sides
0=y^2+14y-240
use quadratic equation to solve which is [tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} =x[/tex] if you have ax^2+bx+c so
a=1
b=14
c=-240
subsitute and get [tex] \frac{-14+/- \sqrt{14^2-4(1)(-240)} }{2(1)} =10 or -24 [/tex] (+/- means that there are 2 equations exg 2+/-8=2+8 and 2-8)
the numbers are 10 and -24
