Answer :
Calculate the density:
[tex]m=8.97 \ g \\ V=0.79 \ cm^3 \\ \\ \rho=\frac{m}{V}=\frac{8.79 \ g}{0.79 \ cm^3} \approx 11.35 \ \frac{g}{cm^3}[/tex]
It's the density of lead, so the answer is C.
[tex]m=8.97 \ g \\ V=0.79 \ cm^3 \\ \\ \rho=\frac{m}{V}=\frac{8.79 \ g}{0.79 \ cm^3} \approx 11.35 \ \frac{g}{cm^3}[/tex]
It's the density of lead, so the answer is C.
Answer: The correct option is Option C.
Explanation:
To identify the sample, we will determine the density of the unknown sample and match it with the specific densities. The equation used to calculate the density of a sample is given by:
[tex]Density=\frac{Mass}{Volume}[/tex]
We are given:
Mass of the sample = 8.97 g
Volume of the sample = [tex]0.79cm^3[/tex]
Putting values in above equation, we get:
[tex]\text{Density of the sample}=\frac{8.97g}{0.79cm^3}=11.35g/cm^3[/tex]
This value of density matches the specific density of lead.
Hence, the correct option is Option C.