Answer :
im assuming that you mean 4/(x+1)-2/(x+2)
first get a common denominator of (x+1)(x+2)
multiply 4/(x+1) times (x+2)/(x+2) and get (4x+8)/[(x+1)(x+2)]
then multiply -2/(x+2) times (x+1)/(x+1) and get (-2x-2)/[(x+1)(x+2)]
next connect like parts
(4x+8-2x-2)/[(x+1)(x+2)]
the answer is (2x+6)/[(x+1)(x+2)]
first get a common denominator of (x+1)(x+2)
multiply 4/(x+1) times (x+2)/(x+2) and get (4x+8)/[(x+1)(x+2)]
then multiply -2/(x+2) times (x+1)/(x+1) and get (-2x-2)/[(x+1)(x+2)]
next connect like parts
(4x+8-2x-2)/[(x+1)(x+2)]
the answer is (2x+6)/[(x+1)(x+2)]
[tex]\frac{4}{x + 1} - \frac{2}{x + 2} = \frac{4(x + 2)}{(x + 1)(x + 2)} - \frac{2(x + 1)}{(x + 1)(x + 2)} = \frac{4x + 8}{x^{2} + 3x + 2} - \frac{2x + 2}{x^{2} + 3x + 2} = \frac{2x + 6}{x^{2} + 3x + 2} [/tex]
