gradient of a straight line through the points (4,6) and (16,54)

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28-04-2015
Mathematics

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gradient of a straight line through the points (4,6) and (16,54)

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Panoyin Panoyin · Answer 1 · 2015-04-28T19:28:22-04:00

Panoyin Panoyin

28-04-2015

[tex]m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{54 - 6}{16 - 4} = \frac{48}{12} = 4[/tex]

[tex]y - y_1 = m(x - x_1) \\ y - 6 = 4(x - 4) \\ y - 6 = 4(x) - 4(4) \\ y - 6 = 4x - 16 \\ y = 4x - 10 [/tex]

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