Answer :

naǫ
[tex](x,y)=(5,8) \\ \\ \hbox{plug the values into the equation:} \\ 7y-3x=11 \\ 7 \times 8-3 \times 5=11 \\ 56-15=11 \\ 41=11 \\ not \ true[/tex]

No, it isn't a solution.

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