Answer :
So when we scale up this image, all points' distances from the center are multiplied by [tex]k[/tex]. We want to then put them back to where they were before.
Thinking about inverse operations, we could just divide by [tex]k[tex], right? But the problem with having a scale factor is we can only multiply.
Think about fractions. Dividing by a fraction is the same as multiplying by the reciprocal, right?
So if we think of [tex]k[/tex] as [tex]\frac{k}1[/tex], then the opposite reciprocal would be [tex]\boxed{\frac{1}k}[/tex]
Thinking about inverse operations, we could just divide by [tex]k[tex], right? But the problem with having a scale factor is we can only multiply.
Think about fractions. Dividing by a fraction is the same as multiplying by the reciprocal, right?
So if we think of [tex]k[/tex] as [tex]\frac{k}1[/tex], then the opposite reciprocal would be [tex]\boxed{\frac{1}k}[/tex]
