Here is our equation.
[tex]h=-16t^2+144t[/tex]
We want to find what [tex]h[/tex] will be when [tex]t=3[/tex].
Let's plug in 3 for [tex]t[/tex] and solve.
[tex]h=-16\times3^2+144\times3[/tex]
[tex]h=-16\times9+144\times3[/tex]
[tex]h=-144+432[/tex]
[tex]\boxed{h=288}[/tex]
