Answered

1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?
a. N₂O₅
b. N₂O₃
c. NO₂
d. NO
e. N2₂O



Answer :

marmal
[tex]M\ N_2=28g/mol\\ 63,8\%--28g\\ 100\%--x\\ x=43,89g[/tex]

43,89g≈44g
44g == 2x 14g (N) + 1x 16x(O)
M N₂O = 44g