So,
There are 4 red marbles.
There are 7 blue marbles.
There are 5 green marbles.
There are 16 marbles in total.
a.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
[tex] \frac{4}{16} \ or\ \frac{1}{4} [/tex]
Next, the probability of selecting a blue marble.
[tex] \frac{7}{16} [/tex]
Multiply the probabilities together.
[tex] \frac{1}{4} * \frac{7}{16} = \frac{7}{64} [/tex]
That is the probability for event a.
b.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.
[tex] \frac{4}{16} \ or\ \frac{1}{4} [/tex]
Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.
[tex] \frac{7}{15} [/tex]
Multiply the probabilities together.
[tex] \frac{1}{4} * \frac{7}{15} = \frac{7}{60} [/tex]
That is the probability for event b.
c.
Obviously:
[tex] \frac{7}{64} \neq \frac{7}{60} [/tex]
So the answer is no.
