Answer :
Assuming uniform distribution and independence, then
P(1st number less than 8 and 2nd number less than 8) =
P(1st number less than 8)*P(2nd number less than 8) =
(7/12)*(7/12) = about 34%
P(1st number less than 8 and 2nd number less than 8) =
P(1st number less than 8)*P(2nd number less than 8) =
(7/12)*(7/12) = about 34%