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A 1.2 kg ball moving due east at 40 m/s strikes a stationary 6.0 kg object. The 1.2 kg ball rebounds to the west at 25 m/s. What is the speed of the 6.0 kg object after the collision



Answer :

v_2' = v_1 + v_1'
So v_2' = 40 + -25
We have set east to be + and west -
Which gives us 15 m/s. So thats how fast the 6 kg object is going.
This is true for an elastic collision.

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