WeirdJason
WeirdJason WeirdJason
  • 14-05-2015
  • Mathematics
Answered

ΔABC is right-angled at A and |AB|=2|AC|. Prove that |BC|^2=5|AC|^2



Answer :

konrad509
konrad509 konrad509
  • 14-05-2015
[tex]|AB|^2+|AC|^2=|BC|^2\\\\ (2|AC|)^2+|AC|^2=5|AC|^2\\ 4|AC|^2+|AC|^2=5|AC|^2\\ 5|AC|^2=5|AC|^2 [/tex]
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