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a circular picture is 8 inches in diameter, part A what is the area of the picture in square inches part B a frame that is 2 inches wide surrounds the picture. what is the total area of the picture and the frame in square inches



Answer :

part a :
Area = π*r² = π(d/2)² = π*(8/2)² =
π*4² = π*16 square inches



Part b
d=8+4 = 12 and r = d/2 = 6inches
We know :

Area = π*r²

Area = π*6²
=36π

Break it down.

Hint : Radius is half the diameter, 8 / 2 = 4

Part A:

A = πr^2

A = π(4)^2

A = π16

Part B :

C = πd

C = π8

but its 2in. wide

C = π8 x 2

C = π16

From the previous question, I know the area is π16

A = π16 + C = π16 = π32




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