Answer :
Use the Pythagorean theorem:
[tex](\hbox{leg})^2+(\hbox{leg})^2=(\hbox{hypotenuse})^2 \\ 10^2+10^2=x^2 \\ 100+100=x^2 \\ x^2=200 \\ x=\sqrt{200} \\ x \approx 14.1[/tex]
The length of the hypotenuse is approximately 14.1 in.
[tex](\hbox{leg})^2+(\hbox{leg})^2=(\hbox{hypotenuse})^2 \\ 10^2+10^2=x^2 \\ 100+100=x^2 \\ x^2=200 \\ x=\sqrt{200} \\ x \approx 14.1[/tex]
The length of the hypotenuse is approximately 14.1 in.
