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Two number cubes are rolled what is the probability that the sum of the numbers rolled is either a 4 or a 10



Answer :

konrad509
[tex]|\Omega|=6^2=36\\ A=\{(1,3),(3,1),(2,2),(4,6),(6,4),(5,5)\}\\ |A|=6\\ P(A)=\dfrac{|A|}{|\Omega|}\\\\ P(A)=\dfrac{6}{36}=\dfrac{1}{6}[/tex]