The area of a trapezium is A= 1/2 h (a+b) where H is the height and a and b are the lengths of the trapezium. Find the area of the trapezium with the following measurements :
h= 2.0 mm, A= 7.5 mm, B= 10.8 mm

Please showing al working! :/



Answer :

so assuming you meant to type a=7.5mm and b=10.8 (uppercase and lowercase letters matter) then


pemdas
parethasees
exponents
mulitplication or division
addition or subtraction


area=1/2 times h times (a+b)
area=1/2 times 2 times (7.5 +10.8)
area=1/2 times 2 times (18.3)
area=1 times (18.3)
area=18.3 square mm also written as 18.3 mm^2

area=18.3 square mm or 18.3mm^2
Area of trapezium=1/2 h(a+b), a=7.5mm, b=10.8mm, h=2.0mm. 1/2 2(7.5+10.8). 1/2 2(18.3). 1/2 36.6. Area of trapezium=18.3sqmm