Answer :
So,
Since this is independent probability, the probability of the event above occurring is:
[tex](probability\ of\ heads)(probability\ of\ even\ no.)[/tex]
First, the probability of landing on heads.
[tex] \frac{1}{2} [/tex]
Now, the probability of rolling an even number.
[tex] \frac{3}{6}\ or\ \frac{1}{2} [/tex]
Plug it into the equation.
[tex] \frac{1}{2} * \frac{1}{2} = \frac{1}{4} [/tex]
The correct option is C.
Since this is independent probability, the probability of the event above occurring is:
[tex](probability\ of\ heads)(probability\ of\ even\ no.)[/tex]
First, the probability of landing on heads.
[tex] \frac{1}{2} [/tex]
Now, the probability of rolling an even number.
[tex] \frac{3}{6}\ or\ \frac{1}{2} [/tex]
Plug it into the equation.
[tex] \frac{1}{2} * \frac{1}{2} = \frac{1}{4} [/tex]
The correct option is C.
