Convert all the equations to slope-intercept form:
[tex]2y-4x=3 \ \ \ |+4x \\
2y=4x+3 \ \ \ |\div 2 \\
y=2x+\frac{3}{2}[/tex]
[tex]A. \\
-2y+4x=1 \ \ \ |-4x \\
-2y=-4x+1 \ \ \ |\div (-2) \\
y=2x-\frac{1}{2} \\ \\
B. \\
3y-6x=6.5 \ \ \ |+6x \\
3y=6x+6.5 \ \ \ |\div 3 \\
y=2x+\frac{13}{6}[/tex]
[tex]C. \\
y-2x=3 \ \ \ |+2x \\
y=2x+3 \\ \\
D. \\
-2y-4x=3 \ \ \ |+4x \\
-2y=4x+3 \ \ \ |\div (-2) \\
y=-2x-\frac{3}{2}[/tex]
Lines A, B and C have the same slope as the line 2y-4x=3, so they are parallel and don't intersect it.
Line D has another slope, so it intersects the line 2y-4x=3.
The answer is D.
