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Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum of two times the number of test tubes and five times the number of beakers is 450. If b is the number of beakers and t is the number of test tubes, the system of linear equations representing this situation is . The number of beakers in the school’s lab is , and the number of test tubes in the school’s lab is



Answer :

b= number of beakers which there are 450 
t= number of test tubes 
the answer is 1.46

Answer:

Number of test tubes is 150 while the number of beakers is 30

Step-by-step explanation:

Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660.

The above expression can be expressed  below

Let the number of test tubes =  t

Let the number of beakers = b

5t - 3b = 660.......................(i)

The sum of two times the number of test tubes and five times the number of beakers is 450.

This can be expressed as follows

2t + 5b = 450..................(ii)

The linear equation is simultaneous equation

5t - 3b = 660.......................(i)

2t + 5b = 450..................(ii)

2t = 450 - 5b

t = 450/2 -5b/2

t = 225  - 5b/2

Insert t in equation (i)

5t - 3b = 660.......................(i)

5(225 - 5b/2)  - 3b = 660

1125  - 25b/2 -3b = 660

1125- 660  = 12.5b + 3b

465  = 15.50b

465/15.50 = b

b = 30

insert b in equation (ii)

2t + 5b = 450..................(ii)

2t + 5(30) = 450

2t = 450 - 150

2t = 300

t = 300/2

t = 150

Number of test tubes is 150 while the number of beakers is 30

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