Answer :
F(in) x d(in)= F(out)x d(out)
A machine has a mechanical advantage of 5.
F(out )= 5xF(in)300 newtons
F(in) = 300 N
F(out)= 5xF(in) = 5x300 N
= 1500 N
Work in = Work out = 3000 N x m3000
N x m = F_in x d_ind_in = 3000 Nxm / F_in = 3000 N x m / 300 N = 10 m3000 Nxm = F_out x d_out d_out = 3000 Nx m / F_out = 3000 N x m / 1500 N = 2 m
A machine has a mechanical advantage of 5.
F(out )= 5xF(in)300 newtons
F(in) = 300 N
F(out)= 5xF(in) = 5x300 N
= 1500 N
Work in = Work out = 3000 N x m3000
N x m = F_in x d_ind_in = 3000 Nxm / F_in = 3000 N x m / 300 N = 10 m3000 Nxm = F_out x d_out d_out = 3000 Nx m / F_out = 3000 N x m / 1500 N = 2 m