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Find the equation of the circle that satisfies the given conditions. Radius 2 and center (4, -7)?



Answer :

[tex]The\ equation\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\\\\center:(a;\ b)\\\\radius:r[/tex]


[tex]Center:(4;-7);\ radius:r=2\\\\(x-4)^2+(y+7)^2=2^2\\\\(x-4)^2+(y+7)^2=4[/tex]

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