Marcia571
Answered

please help How much heat does it take to raise the temperature of 9.0 kg of wood from 12C to 97C? The specific heat of wood is 1.68 kJ/(kgC). Use Q = mc(Tf - Ti). A. 760 kJ B. 1300 kJ C. 180 kJ D. 1500 kJ



Answer :

AstronautA
Q=mc(Tf-Ti)
   = (9Kg)(1.68 KJ/KgC)(97-12)
   = 1285.2 KJ
   ~ 1300 KJ

Answer:

[tex]Q = 1300 kJ[/tex]

Explanation:

As we know that heat require to change the temperature of the object is given as

[tex]Q = mC \Delta T[/tex]

here we know that

m = mass = 9 kg

C = 1.68 kJ/kg

[tex]\Delta T = 97 - 12[/tex]

[tex]\Delta T = 85 degree C[/tex]

now from above formula we will have

[tex]Q = 9\times 1.68 \times 10^3 \times 85[/tex]

[tex]Q = 1300 kJ[/tex]