Answer :
Given;
Area of the traingle = 230.86 sq. inches
Height of the triangle = 23.8 sq. inches
We have,
Area of the triangle = [tex] \frac{1}{2} bh[/tex]
where,
b = base of the traingle
h = height of the triangle
Now,
Substituting the given info. we get,
[tex]230.86 = \frac{1}{2} ~ b~(23.8)[/tex]
[tex] \frac{230.86 ~*~2}{23.8} = b[/tex]
[tex]b = 19.4[/tex]
So, the base of the triangle is 19.4 inches
Area of the traingle = 230.86 sq. inches
Height of the triangle = 23.8 sq. inches
We have,
Area of the triangle = [tex] \frac{1}{2} bh[/tex]
where,
b = base of the traingle
h = height of the triangle
Now,
Substituting the given info. we get,
[tex]230.86 = \frac{1}{2} ~ b~(23.8)[/tex]
[tex] \frac{230.86 ~*~2}{23.8} = b[/tex]
[tex]b = 19.4[/tex]
So, the base of the triangle is 19.4 inches
