[tex] \frac{3}{8} ... \frac{5}{16} [/tex]
First, find the least common denominator between the two.
Since 8 is a factor of 16, the LCD is 16.
[tex] \frac{3*2}{8*2} [/tex]
[tex] \frac{3}{8}= \frac{6}{16} [/tex]
Now, you can compare the numerators.
[tex]6>5[/tex]
Since 6 is greater than 5, you know that [tex] \frac{6}{16} > \frac{5}{16} [/tex].
Therefore, we now know that [tex] \frac{3}{8} [/tex] is larger.
