Answer :
The reaction formula is HNO3 + KOH = KNO3 + H2O. The mole number of HNO3 and KOH is the same. So the concentration of HNO3 is 150*0.5/50=1.5 M. So the answer is (2).
Answer : The correct option is, (2) 1.5 M
solution :
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]HNO_3[/tex] solution = ?
[tex]V_1[/tex] = volume of [tex]HNO_3[/tex] solution = 50 ml
[tex]M_2[/tex] = molarity of KOH solution = 0.50 M
[tex]V_2[/tex] = volume of KOH solution = 150 ml
Now put all the given values in the above law, we get the volume of [tex]HNO_3[/tex] solution.
[tex]M_1\times (50ml)=(0.50M)\times (150ml)[/tex]
[tex]M_1=1.5M[/tex]
Therefore, the concentration of [tex]HNO_3[/tex] is, 1.5 M