Answer :
Answer;
(4) 2 L of H2(g) and 2 L of Cl2(g)
Explanation;
- At STP (standard temperature and pressure) 2 L of hydrogen gas and 2 L of chlorine gas will contain the same number of molecules.
- 1 mole of a gas occupies a volume of 22.4 liters at STP. Both hydrogen and chlorine are gases, thus equal volumes of the two gases ( 2 liters) will be equivalent to 2/22.4 moles (0.0893 moles)
- 1 mole is equivalent to 6.0 ×10^23 particles . Thus 2 L of each gas would contain 5.357 × 10 ^22 molecules (0.0893 × 6 ×10^23).