Answer :
Plug in the values into this equation
Ka = [H+][CO3 2-]/[HCO3-]
[ ] = concentration
then solve for [H+] if you know the Ka of HCO3-, and then take the -log[H+] to find the pH.
The Ka of HCO3- = 5.6x10^-11
Ka = [H+][CO3 2-]/[HCO3-]
[ ] = concentration
then solve for [H+] if you know the Ka of HCO3-, and then take the -log[H+] to find the pH.
The Ka of HCO3- = 5.6x10^-11
