The volume of 6.00M HCl needed to make 319 ml of 6.80M HCl

The mole number of the solute after dilution is constant. So the mole number of 319 ml of 6.80 M HCl is 6.80*319*10^(-3)=2.17 mol. So the volume of 6.00 M HCl needed is 2.17/6.00=0.362 L=362 ml.

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BarrettArcher BarrettArcher · Answer 2 · 2019-03-06T10:16:38-05:00

Answer : The volume of 6.00 M HCl needed are, 361.5 ml

Solution :

According to the neutralization law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of HCl solution = 6.00 M

[tex]V_1[/tex] = volume of HCl solution = ?

[tex]M_2[/tex] = molarity of another HCl solution = 6.80 M

[tex]V_2[/tex] = volume of another HCl solution = 319 ml

Now put all the given values in the above law, we get the volume of HCl solution.

[tex](6.00M)\times V_1=(6.80M)\times (319ml)[/tex]

[tex]V_1=361.5ml[/tex]

Therefore, the volume of 6.00 M HCl needed are, 361.5 ml