RaisaMindell204
Answered

What is the total energy released when
9.11 × 10^−31 kilogram of mass is converted into
energy?
(1) 2.73 × 10^−22 J (3) 9.11 × 10^−31 J
(2) 8.20 × 10^−14 J (4) 1.01 × 10^−47 J



Answer :

Giovi
I found (2).
Using [tex]E=m c^{2} =9.11* 10^{-31}* (3*10^{8} )^{2} =8.2* 10^{-14}J [/tex]

Answer:

The correct answer is option 2,

The total energy released is [tex]8.20 * 10^{-14} J\\[/tex]

Explanation:

As per Einstein theory of relativity,

[tex]E = mc^2\\[/tex]

where

"E" is the energy produced by mass conversion

"m" is the mass converted

"c" speed of light

Substituting the given values in above equation we get -

[tex]E = (9.11 * 10^{-31}) Kg * ( 3 * 10^{8} \frac{m}{s} )^2\\= 8.20 * 10^{-14} J\\[/tex]

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