Answer :
[tex]3m^2n+12mn^2[/tex]
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)
Therefore the answer is 3mn (#3)
In both the sets, 3 and m as well as n can be found as common factors.
So,
3mn( m+4n)
Therefore the answer is 3mn (#3)