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What is the specific heat of metal if its mass is 26.86g and it requires 418.6 J of heat energy to raise its temperature from 27.4 oC to 67.3°C?



Answer :

astonkute8
Formula: q=m*c*(change in T)
q= 418.6
m=26.86
c= X(unknown) 
(Change in T)= (67.3-27.4 = 39.9) 

Now you solve for X, I got .391. 
So the specific heat of this certain metal is .391 j/gram C


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