A small ice cream shop has 14 flavors of ice cream and 8 kinds of toppings for its sundans. How many different selections of one flavor of ice cream and one kind of topping are possible?



Answer :

Answer:

112 possible outcomes

Step-by-step explanation:

We can use the fundamental counting principle to determine the number of outcomes:

14 flavors * 8 toppings = 112 possible outcomes

To calculate the total number of different selections of one flavor of ice cream and one kind of topping possible, you multiply the number of ice cream flavors (14) by the number of toppings (8), resulting in 112 different selections.

The question asks for the number of different selections of one flavor of ice cream and one kind of topping that are possible at a small ice cream shop that has 14 flavors of ice cream and 8 kinds of toppings. This is a straightforward combinations without repetition problem because you are choosing one item (ice cream flavor) and then another item (topping) independently from the respective totals, without repeating either choice.

To find the total number of combinations possible, you simply multiply the number of choices for ice cream flavors (14) by the number of choices for toppings (8). Hence, the total number of different combinations would be 14 * 8 = 112 possible selections.

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