Answered

A coin is thrown straight downward from the top of the building after 3.50 s, the coin hits the ground at -50.0 m/s the acceleration is -9.8 m/s2 what is the change in height of the coin. Y=[ ] m.



Answer :

MathPhys

Answer:

-235 m

Explanation:

The coin is a projectile in free fall. We can use kinematics to find the displacement as a function of the initial velocity, acceleration, and time.

Take up to be positive. Given:

u = -50 m/s

a = -9.8 m/s²

t = 3.50 s

Find: s

s = ut + ½ at²

s = (-50 m/s) (3.50 s) + ½ (-9.8 m/s²) (3.50 s)²

s = -235 m