Answer:
A) 3
Step-by-step explanation:
- We need to find the area of four walls and the area of ceiling.
Area of four walls:
[tex]\sf length = l = 11\dfrac{1}{2} \ ft = \dfrac{23}{2} \ ft[/tex]
Width = w = 26 ft
height = h = 9 ft
[tex]\boxed{\bf Area \ of \ four \ walls = 2h *(l +w)}[/tex]
[tex]\sf = 2 * 9 * \left( \dfrac{23}{2}+26\right)\\\\\\= 2 *9 * \left( \dfrac{23}{2}+ \dfrac{26*2}{1*2}\right)\\\\\\= 2* 9 * \left( \dfrac{23}{2}+ \dfrac{52}{2}\right)\\\\\\= 2 * 9 * \dfrac{75}{2}\\[/tex]
= 9 * 75
= 675 square feet
Area of ceiling:
[tex]\boxed{\bf Area \ of \ ceiling = l*w}[/tex]
[tex]\sf = \dfrac{23}{2}*26\\\\\\= 23 * 13\\\\= 299 \ ft^2[/tex]
Area to be painted = area of the walls + area of ceiling
= 675 + 299
= 974 square feet
- It is given that one gallon covers 400 square feet. So, to cover 974 square feet 3 gallon cans are required.
