Answer:
To find the boiling point of chloroform (CHCl3) in Kelvin, you can use the equation:
ΔGvap = ΔHvap - TΔSvap = 0
Where ΔGvap is the change in Gibbs free energy during vaporization, ΔHvap is the enthalpy of vaporization, ΔSvap is the entropy of vaporization, and T is the temperature in Kelvin.
Rearranging the equation to solve for T:
T = ΔHvap / ΔSvap
Substituting the given values:
T = (29.2 kJ/mol) / (87.5 J/(K⋅mol))
Convert kJ to J: 29.2 kJ/mol = 29,200 J/mol
T ≈ (29,200 J/mol) / (87.5 J/(K⋅mol))
T ≈ 333 K
So, the boiling point of chloroform in Kelvin is approximately 333 K.
