Answer :
Answer:
x = 0 and y = 2
Step-by-step explanation:
To solve the system of equations 3x + 24y = 48 and 3x=12- 6y using the addition method, follow these steps:
Write the equations:
[tex]3x + 24y = 48[/tex]
[tex]3x = 12-6y [/tex]we can write this equation as:
[tex] 3x +6y = 11 [/tex]
Identify a variable to eliminate:
In this case, we can eliminate 3x by subtracting the second equation from the first equation.
Perform the subtraction:
Subtract the second equation from the first equation:
[tex](3x + 24y) - (3x + 6y) = 48 - 12[/tex]
Simplify the left-hand side:
[tex]3x + 24y - 3x - 6y = 36[/tex]
Combine like terms:
[tex]18y = 36[/tex]
Solve for y:
Divide both sides by 18:
[tex]y = \frac{36}{18}[/tex]
[tex]y = 2[/tex]
Substitute y back into one of the original equations to solve for x:
Let's use the second equation 3x + 6y = 12:
[tex]3x + 6(2) = 12[/tex]
Simplify:
[tex]3x + 12 = 12[/tex]
Subtract 12 from both sides:
[tex]3x = 12 - 12[/tex]
[tex]3x = 0[/tex]
Solve for x by dividing both sides by 3:
[tex]x = \frac{0}{3}[/tex]
[tex]x = 0[/tex]
Therefore, the solution to the system of equations is x = 0 and y = 2.
Note: Here we perform subtraction not addition
