angel0741 angel0741

20-04-2024
Mathematics

Answered

question fifteen
solve
[tex]{x}^{2} + 10x + 21 \geqslant 0[/tex]

Answer :

georgepahno georgepahno

20-04-2024

Answer:

x² + 10x + 21 ≥ 0

(x + 7)(x + 3) ≥ 0

x ≤ -7 or x ≥ -3

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