angel0741 angel0741

20-04-2024
Mathematics

Answered

[tex]y = {x}^{2} + 3x - 18[/tex]
[tex]x + 2y + 14 = 0[/tex]
solve the simultaneous equations.

Answer :

georgepahno georgepahno

20-04-2024

Answer:

x + 2(x² + 3x - 18) + 14 = 0

x + 2x² + 6x - 36 + 14 = 0

2x² + 7x - 22 = 0

(2x + 11)(x - 2) = 0

2x + 11 = 0 or x - 2 = 0

x = -5.5 or x = 2

(-5.5)² + 3(-5.5) - 18 = -4.25

2² + 3(2) - 18 = -8

{(-5.5, -4.25), (2, -8)}

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