Answer:
[tex]1.91 {cm}^{2} [/tex]
Step-by-step explanation:
Area of the shaded portion = Area of the sector OMN - Area of the triangle OMN =
[tex] \frac{theta}{360} \times \: \pi \: {r}^{2} - \frac{1}{2}ab \sin(theta) [/tex]
[tex] = \frac{50}{360} \times 3.14 \times {6}^{2} - ( \frac{1}{2} \times 6 \times 6 \times \sin(50)) [/tex]
[tex] = 15.70 - 13.79[/tex]
[tex] = 1.91 \: {cm}^{2} [/tex]